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Page 752
This assumes that n0¹ 0 and hence C1 actually enters and leaves the server. If n0 = 0 then
0752-01.gif
as no item entered or left the server. We combine these as
0752-02.gif
where d0 is the probability that n0 = 0. d0 has only two values: d0 = 0 when n0¹ 0 and d0 = 1 when n0 = 1, so that n0d0 = 0 and 0752-03.gif.
Now find E(d), which lies between 0 and 1:
0752-04.gif
by the stationarity assumption.
Now E(r) is the expected number of arrivals during a service time; i.e.,
0752-05.gif
so that
0752-06.gif
The expectation that the server is idle, E(d), is
0752-07.gif
Now suppose we generalize equation E.1 for time intervals i and i - 1 and we square both sides of equation E.1.
0752-08.gif
Taking the expcted value of both sides,
0752-09.gif
again by stationary 0752-10.gif. Also, since ni-1, ri, di-1 are independent and E(ri) = E(r), etc., we have
0752-11.gif

 
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